test(criteria): 规范加 §1.5「两张表各缺一半时按 id 联接,不按相邻关系配对」(pi 的建议 + 我方实测的串行实例)

This commit is contained in:
2026-09-14 15:20:39 +08:00
parent dbdb2f5039
commit f412751b37
2 changed files with 12 additions and 1 deletions

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@ -49,7 +49,7 @@ if (!existsSync(CRITERIA_DOC)) {
process.exit(1);
}
const criteriaDoc = readFileSync(CRITERIA_DOC, 'utf8');
for (const must of ['配对/解析', 'allow-list', '变异验证', '剥掉注释', '按行', '自报条数', '只支撑你看到的那一层', '已经在某个提交里', '自带修法']) {
for (const must of ['配对/解析', 'allow-list', '变异验证', '剥掉注释', '按行', '自报条数', '只支撑你看到的那一层', '已经在某个提交里', '自带修法', '按 id 联接']) {
if (!criteriaDoc.includes(must)) {
console.error(`✗ 判据规范里少了「${must}」这条 —— 规则被删掉了还是搬走了?`);
process.exit(1);