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fix: 简化密码获取逻辑，无论如何都从容器获取密码

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2026-04-08 23:05:29 +08:00
parent 25b8365cc7
commit 537ee260fd
1 changed files with 5 additions and 4 deletions
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9
scripts/install_neo4j_ubuntu.sh
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@ -79,7 +79,7 @@ else
elif [ -n "$STOPPED" ]; then elif [ -n "$STOPPED" ]; then
echo " 找到已停止的 Neo4j 容器: $STOPPED" echo " 找到已停止的 Neo4j 容器: $STOPPED"
docker start "$STOPPED" 2>/dev/null || true docker start "$STOPPED" 2>/dev/null || true
sleep 3 sleep 5
EXISTING="$STOPPED" EXISTING="$STOPPED"
else else
# 没有已有容器，创建新的 # 没有已有容器，创建新的
@ -89,7 +89,7 @@ else
-e NEO4J_AUTH=neo4j/${NEO4J_PASS} \ -e NEO4J_AUTH=neo4j/${NEO4J_PASS} \
-e NEO4J_PLUGINS='["apoc"]' \ -e NEO4J_PLUGINS='["apoc"]' \
neo4j:5 || true neo4j:5 || true
sleep 15 sleep 20
echo " Neo4j Docker 容器已启动" echo " Neo4j Docker 容器已启动"
echo " 密码: $NEO4J_PASS" echo " 密码: $NEO4J_PASS"
NEO4J_PASSWORD="$NEO4J_PASS" NEO4J_PASSWORD="$NEO4J_PASS"
@ -97,11 +97,12 @@ else
EXISTING="openclaw-neo4j" EXISTING="openclaw-neo4j"
fi fi
# 获取密码 # 无论如何都从容器获取密码
if [ -z "$NEO4J_PASSWORD" ]; then if [ -n "$EXISTING" ]; then
NEO4J_AUTH=$(docker inspect "$EXISTING" --format '{{.Config.Env}}' 2>/dev/null | tr ' ' '\n' | grep NEO4J_AUTH | cut -d'=' -f2) NEO4J_AUTH=$(docker inspect "$EXISTING" --format '{{.Config.Env}}' 2>/dev/null | tr ' ' '\n' | grep NEO4J_AUTH | cut -d'=' -f2)
if [ -n "$NEO4J_AUTH" ]; then if [ -n "$NEO4J_AUTH" ]; then
NEO4J_PASSWORD=$(echo "$NEO4J_AUTH" | cut -d'/' -f2) NEO4J_PASSWORD=$(echo "$NEO4J_AUTH" | cut -d'/' -f2)
echo " 获取到密码: $NEO4J_PASSWORD"
fi fi
fi fi
else else